From f1a40d304b105b9116f78de58ae398a4403e215c Mon Sep 17 00:00:00 2001
From: Roberto Raggi <qtc-committer@nokia.com>
Date: Tue, 3 Feb 2009 12:50:53 +0100
Subject: [PATCH] Fixes: Member completion when the symbol's type is ClassTy.
For example,
struct {
int a, b
} foo;
int main() {
foo. <-
}
---
src/plugins/cpptools/cppcodecompletion.cpp | 6 +++++-
1 file changed, 5 insertions(+), 1 deletion(-)
diff --git a/src/plugins/cpptools/cppcodecompletion.cpp b/src/plugins/cpptools/cppcodecompletion.cpp
index b6bac92bf9b..1f5bb7e1f4e 100644
--- a/src/plugins/cpptools/cppcodecompletion.cpp
+++ b/src/plugins/cpptools/cppcodecompletion.cpp
@@ -598,7 +598,9 @@ bool CppCodeCompletion::completeMember(const QList<TypeOfExpression::Result> &re
if (ReferenceType *refTy = ty->asReferenceType())
ty = refTy->elementType();
- if (NamedType *namedTy = ty->asNamedType()) {
+ if (Class *classTy = ty->asClass()) {
+ classObjectCandidates.append(classTy);
+ } else if (NamedType *namedTy = ty->asNamedType()) {
// ### This code is pretty slow.
const QList<Symbol *> candidates = context.resolve(namedTy->name());
foreach (Symbol *candidate, candidates) {
@@ -697,6 +699,8 @@ bool CppCodeCompletion::completeMember(const QList<TypeOfExpression::Result> &re
++m_startPosition;
namedTy = ptrTy->elementType()->asNamedType();
}
+ } else if (Class *classTy = ty->asClass()) {
+ classObjectCandidates.append(classTy);
} else {
namedTy = ty->asNamedType();
if (! namedTy) {
--
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