QmlDesigner: Remove 'variant' as qml type

'variant' has been removed from the qml grammar: d1f019567, it's now 'var' only.

src/plugins/qmldesigner/core/metainfo/propertymetainfo.cpp

@@ -420,14 +420,12 @@ QVariant PropertyMetaInfo::castedValue(const QVariant &originalVariant) const
         return variant;
     } else if (typeId == QVariant::UserType && m_data->type == QLatin1String("QVariant")) {
         return variant;
-    } else if (typeId == QVariant::UserType && m_data->type == QLatin1String("variant")) {
-        return variant;
     } else if (typeId == QVariant::UserType && m_data->type == QLatin1String("var")) {
         return variant;
     } else if (variant.type() == QVariant::List && variant.type() == QVariant::List) {
         // TODO: check the contents of the list
         return variant;
-    } else if (type() == "var" || type() == "variant") {
+    } else if (type() == "var") {
         return variant;
     } else if (type() == "alias") {
         // TODO: The QML compiler resolves the alias type. We probably should do the same.

src/plugins/qmldesigner/core/model/texttomodelmerger.cpp

@@ -185,7 +185,7 @@ static inline int propertyType(const QString &typeName)
         return QMetaType::type("QString");
     else if (typeName == QLatin1String("url"))
         return QMetaType::type("QUrl");
-    else if (typeName == QLatin1String("var") || typeName == QLatin1String("variant"))
+    else if (typeName == QLatin1String("var"))
         return QMetaType::type("QVariant");
     else
         return -1;